#include <math.h>
double fmod( double x, double y );
函数返回参数 x/y 的余数。
#include <stdio.h>
#include <math.h>
int main(void)
{
double x = 5.0, y = 2.0;
double result;
result = fmod(x,y);
printf("The remainder of (%lf / %lf) is \
%lf\n", x, y, result);
return 0;
}输出结果:
The remainder of (5.000000 / 2.000000) is 1.000000