OpenJPA

OpenJPA 是 Apache 组织提供的开源项目,它实现了 EJB 3.0 中的 JPA 标准,为开发者提供功能强大、使用简单的持久化数据管理框架。OpenJPA 封装了和关系型数据库交互的操作,让开发者把注意力集中在编写业务逻辑上。

OpenJPA 抛出 The type class xxx has not been enhanced 错误

本文将解决 OpenJPA 抛出 The type class xxx has not been enhanced 错误。

OpenJPA FailedObject: * [org.apache.openjpa.util.IntId] [java.lang.String] 错误

Exception in thread "main" <openjpa-2.4.2-r422266:1777108 nonfatal general error> org.apache.openjpa.persistence.PersistenceException: null FailedObject: 351 [org.apache.openjpa.util.IntId] [java.lang.String]

OpenJPA抛出 The type * has not been enhanced 错误

本文将介绍怎样处理JPA抛出的“org.apache.openjpa.util.MetaDataException: The type "class com.huangx.openjpa.model.User" has not been enhanced.”错误。

严重 org.apache.tomcat.util.bcel.classfile.ClassFormatException: Invalid byte tag in constant pool: 19

严重: Unable to process Jar entry [module-info.class] from Jar [jar:file:/E:/workspaces/safety/safety/app_server/target/app_server/WEB-INF/lib/lombok-1.16.22.jar!/] for annotations org.apache.tomcat.util.bcel.classfile.ClassFormatException: Invalid byte tag in constant pool: 19

解决JPA “Null value was assigned to a property of primitive type setter of” 异常

org.springframework.orm.jpa.JpaSystemException: Null value was assigned to a property of primitive type setter of com.huangx.model.entity.User.userId; nested exception is org.hibernate.PropertyAccessException: Null value was assigned to a property of primitive type setter of com.huangx.model.entity.User.userId 错误信息

OpenJPA之使用getSingleResult报异常NoResultExceptionNo entity found for query

本文将介绍怎样去处理 Hibernate JPA 使用 getSingleResult() 报异常 NoResultExceptionNo entity found for query 错误。

首页 1 末页 共6/1页
关于
本网站专注于 Java、数据库(MySQL、Oracle)、Linux、软件架构及大数据等多领域技术知识分享。涵盖丰富的原创与精选技术文章,助力技术传播与交流。无论是技术新手渴望入门,还是资深开发者寻求进阶,这里都能为您提供深度见解与实用经验,让复杂编码变得轻松易懂,携手共赴技术提升新高度。如有侵权,请来信告知:hxstrive@outlook.com
公众号